Hardy-Weinberg problem help? (AP Biology Lab 8)? - hardy weinberg problems in ap biology lab 8
My question is:
55% of the population of North America is the dominant phenotype (Taster PTC), and 45%) have the recessive phenotype (induction. What is the frequency of each allele? (p = dominant, recessive = q) Moreover, heterozygous what percentage of the population? (2 xpxq) Please show work.
Tuesday, January 19, 2010
Hardy Weinberg Problems In Ap Biology Lab 8 Hardy-Weinberg Problem Help? (AP Biology Lab 8)?
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1 comments:
It should say: "Assuming that the population is in equilibrium, but Nevermind.
For a few alleles:
(p + q) = 1 [all relevant alleles in the population]
and the balance
(p + q) ^ 2
is
p ^ 2 + 2PQ + Q ^ 2 = 1
Representative homozygous / heterozygous / homozygous alleles combi nations or national.
However, the dominant phenotype is useful in itself, but the expression of recessive, it must represent the homozygous recessive genotype alone, and then you can plug in the second equation to find the frequency (the recessive allele q).
45% 1
0.45 = q ^ 2
0671 (3DP) = q (frequency of the recessive allele)
It also tells us (from the first equation) the frequency of the dominant allele (P) is 1 to 0.671 = 0.329
Now links back to some of the second equation of the heterozygous dudes.
2pq = 2 x 0.671 x 0.329 = 0.442 (3DP)
So it is little more than 44% of the population who are heterozygous.
I drank so shouProbably double check to AP.
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